How to solve difficult Time and Work problems in simpler steps, type 3
How to solve difficult time and work problems is explained by solving selected time and work problems with groups of men and women working.
How to solve difficult time and work problems is explained by solving selected time and work problems with groups of men and women working.
A simple or compound event (consisting of more than one event) goes on happening systematically at regular intervals till a point just before the end. With each occurrence of the event problem parameters change. The end is reached before the full impact of the event along with the change can happen. This is the boundary to be found out before solving the problem...
In 42 days 40 men complete a work. As it happened, instead of all of them working together to finish the job, they started working together, but at the end of every 10th day 5 men left. In how many days would then the work be completed? Rich time and work concept of Mandays technique along with natural number concepts deliver speedy solution...
A concise description on how to solve profit and loss problem in a few steps using basic and advanced profit and loss concepts and techniques.
Usually time and distance problems involve objects moving on fixed stationary ground base. When the base starts moving, an additional level of complexity is introduced. These are problem areas favorable for applying very basic relative speed concepts and arrive at solution in a few steps...
Percentage concepts for SSC CGL, Bank PO covers basic and advanced percentage techniques for solving the competitive exam problems of all types.
Law of sines and cosines relate side with sine and cosine of an angle opposite the side in triangle. By sine law, ratios of side to sine of angle are equal.
Centroid divides triangle area into 3 equal parts formed by the longer median segments at centroid and 6 equal parts by all six median segments at centroid.
Relation between median and sides of triangle: Sum of two sides is larger than the median from common vertex and three times sum of squares of length of sides equals four times the squares of medians of a triangle.
Sometimes in the breakneck hurry while struggling with the questions in a cutting edge leading selection test you might meet a problem that doesn't seem right somehow. You figure out the only way to arrive at the solution but out of sheer curiosity you check back the solution value with the given values to verify the sanctity of the problem definition...