NYT hard Sudoku 24 Feb 2021: Solution for Beginners | Suresolv

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NYT hard Sudoku 24 Feb 2021: Solution for Beginners

NYT hard Sudoku 24 Feb 2021 Solution for Beginners

NYT hard Sudoku 24th February, 2021: Easy to understand Solution in details

In this solution to NYT hard Sudoku Feb 24, 2021, each step is explained for even a beginner to understand. Hard Sudoku not any more beyond reach.

How to find the valid single digit for empty cells and achieving breakthroughs by Sudoku techniques shown.

Sections are,

  1. Sudoku terminologies used.
  2. Sudoku techniques to solve hard Sudoku puzzles.
  3. Solution to the hard Sudoku 24th Feb 2021 of New York Times.

To skip the terminologies and move on to Sudoku techniques, click here.

And to skip both and move on to the solution direct, click here.


Terminologies used in explaining solution to the NYT hard Sudoku

Row column labels and names for 9 cell squares

The 9 by 9 Sudoku game has 81 cells in 9 rows and 9 columns.

Rows are labelled R1 to R9 and columns C1 to C9.

81 cells are further divided into 9 groups of 9 square cells. These are either referred as top - left, middle, right; bottom - left, middle, right and left middle, central middle and middle right.

These 9 square cell groups are also referred by their specific labels joining the labels for the three rows and three columns. For example the specific label for the left middle 9 cell square will be R4R5R6-C1C2C3.

Convention followed is to mention row label suffixed by the column label. For example the top leftmost cell is referred as R1C1.

Sudoku rules

9 by 9 Sudoku has three conditions for a digit to occupy a cell,

  1. No digit can be repeated in any row. Every row must have the 9 digits 1 to 9 without repetition.
  2. No digit can be repeated in any column. Every column must have the 9 digits from 1 to 9 without repetition.
  3. Each of the 9 numbers of 9 cell squares must be filled up by exactly 9 digits from 1 to 9 without repeating any digit.

Sudoku techniques to make a breakthrough using specific patterns in the digits

Row column scan for a digit

This is the simplest for identifying a cell where only one digit CAN be placed. No other cell in the 9 cell square, the row or the column containing this specific cell would have this VALID digit except this specific cell that you have found.

In the Sudoku puzzle figure below, by row column scan for digit 1 on top right 9 cell square R1R2R3-C7C8C9, with 1 in row R3, and 1 in column C8, 4 out of 5 empty cells in the 9 cell square are invalid for placing 1. As a result, the digit 1 can be placed in the single remaining cell → R1C9 1. It is the single digit candidate for the single cell R1C9.

Possible digit subset (DS) in a cell

For every empty cell there will be a subset of the 9 digits each of which will be a potential candidate for the cell. This is the possible digit subset or possible DS for an empty cell.

In the hard Sudoku puzzle figure below, possible DS for R3C7 is [3,4,6]. These three digits do not appear in the parents: top right 9 cell square, the parent row R3 and the parent column C7.

In the 9 cell square, filled DS is [2,7,8,9]. Cell R3C7 is in two more affecting areas, the row R3 that has filled DS [1,7,8,9] and the column C7 with filled DS [2,5,8,9]. These two together has [1,5] extra to what the 9 cell square has.

The filled DS for R2C7 becomes [1,2,5,7,8,9]. Possible digit subset [3,4,6] are missing in this set of filled digits and these are the only digit candidates or possible DS for R2C7 that can occupy the empty cell.

Instead of three possible digits, if it were a single possible digit, the cell would be filled with the digit and we would have a hit.

Enumerate the possible digit for cell R2C8. Filled DS for this cell is [1,2,3,4,6,7,8,9] with only 5 missing. Possible DS is single digit 5 → R2C8 5. A hit obtained.

By the term DS in the solution, possible digit subset is indicated. 

possible digit DS enumeration for an empty cell

Digit subset analysis or DSA

When no valid cell by row column scan is visible, try to find a cell for which DS has a single digit. The cell will then have a valid digit and complexity of the game will reduce a little.

As a strategy, DS is evaluated when promise of a simplifying pattern is expected. DS is generally evaluated in heavily filled up zones to keep its length short. This speeds up solution and reduces labor.

This technique is still easy and is the savior oftentimes.

Cycle of digits

If 2 digits, say [4,6], appear as a lone pair in 2 cells (without any other digits possible in the two cells) of a 9 cell square, a column or a row, a Cycle of 2 digits is formed. These two digits have to be placed in either of these two cells in the Cycle and in no other cell of the parent zones 9 cell square, the column or the row containing the lock. (a ZONE is a 9 cell square, a row or a column).

The two digits can then be eliminated from all the DSs of the parent zones of the Cycle.

A Cycle of 3 digits in 3 cells are encountered often. 4 cell Cycles can also be useful if it can be located.

Cycles are valuable patterns to identify.

Single digit lock - Conditions for single digit lock - how to identify it

Two conditions for single digit lock pattern,

  1. the digit can be placed in only two or three cells of a column or a row, AND,
  2. the locking cells must also be in SAME 9 cell square.
  3. the locked digit should not be present as a single cell candidate in both the adjacent two 9 cell squares through which the locked column or row passes.

The following shows and example of single digit lock of 5 in cells R7C1 and R9C1.

sudoku single digit lock: what it is and what it does

How a single digit lock is formed

Look at columns C1, C2 and C3 in the bottom left 9 cell square R7R8R9-C1C2C3. Out of 3 empty cells, the cell R7C3 is debarred for placing digit 5 as column C3 has a 5 and it lights up the cell for digit 5.

5 can appear only in two cells in column C1, R7C1 and R9C1 and in no other cell in the 9 cell square or the column C1.

It is locked inside these two cells in C1 and 9 cell parent square.

How a Sudoku single digit lock is used - What it does

The locked digit 5 eliminates itself from the DSs of the other two empty cells R5C1 and R6C1 and a new Cycle (2,3) is created in C1.

Focus again on the bottom left 9 cell square. With Cycle (2,3) in C1, another Cycle (5,9) is formed in the two cells of the 9 cell square. As a result, digit 1 becomes the only digit left and cell R7C3 only cell left for it.

Still more happens. With 1 in C3 now, digit 9 now must occupy the cell R6C3.

These two single digit candidates obtained by the single digit lock of 5 affects other cells and breaks the bottleneck.

As a strategy, always form a single digit lock as soon as it is discovered.

It is a powerful digit pattern. Even if its effect is not immediate, it should have positive results later.


The NYT hard Sudoku Feb 24, 2021

nytimes hard sudoku 24 february 2021

Solution to the NYT hard Sudoku Feb 24, 2021 for beginners

Scan for 1 on R3, C8 → R1C9 1. Scan on R9, C8, C9 → R8C7 1.

Scan for 5 on R7, R8 → R9C2 5.

DS [3,4,5,6] in top right 9 cell square → DSA on R2C8: digits [3,4,6] → R2C8 5.

Scan for 5 on R1, R2 → R3C3 5.

Scan for 6 on row R3: 6 in top middle square, 6 not valid in R3C4, R3C6, 6 in C9 → R3C7 6 as the only cell in R3 for 6 → R1C8 3 → R3C9 4.

Cycle (8,9) in R8C8, R9C8 in C8 and digit [8,9] in C7 → Cycle (8,9) force formed in R4C9, R6C9 in C9 → DS [3,7] in R9C9 with 5 in R8, R9 and 3 in R9 → R9C9 7 → R8C9 3 → R5C9 5.

With 2 in R6, DS [2,6] in C8 in R6C8 → R6C8 6 → R7C8 2.

With 3 in R5, scan for 3 on right middle 9 cell square → R4C7 3 → R5C7 7.

Scan for 5 on left middle 9 cell square, 5 in R5, C2, C3 → R4C1 5.

Parallel scan for 8 on empty cells of column C1 → 8 in top left 9 cell square, 8 in R6.

R7C1 8 as the only cell in C1 for 8.

Scan for 8 on top middle 9 cell square: 8 in R1, R3, C5 → R2C6 8.

DS [1,2,6] in three empty cells of R5: Parallel scan for 6 on R5: R1, C3 has 6 → R5C6 6. Scan for 6 in bottom middle 9 cell square: 6 in R7, R8, C4, C6 → R9C5 6.

R9C7 4 as the only digit left in C7.

Scan on 5 in central middle square: 5 in R4, R5, C5, C6 → R6C4 5.

More next stage.

For most of the empty cells this time DSs have been enumerated.

Results shown below.

NYT hard Sudoku 24 Feb 2021: Solution for Beginners Stage 1

Whatever possible row column scan, Cycles and DSAs have been used up in single digit candidates got till now.

With the cells fairly filled up, effort is now less in enumerating the DSs of empty cells.

Have to discover a breakthrough pattern in these sets of possible digits in the cells.

And indeed it is there right in front in the form of the single digit lock on 2 in R8C2, R8C3 because of 2 in R7.

Observe that the 2 in DS [2,4,7,9] in R8C5 and DS [2,4,7,8,9] in R8C4 are crossed off. These two cells cannot have 2 because the bottom left 9 cell square has 2 locked in R8.

You may wonder, why so much fuss on this little thing!

Great things will happen. Wait and see.

Parallel scan for 2 on column C5: single digit lock on 2 in R8, 2 in R7, 2 in R6 and 2 in R2 → R4C5 2.

We'll show more simplification next stage.

The single important breakthrough is shown below.

NYT hard Sudoku 24 Feb 2021: Solution for Beginners Stage 2

Scan for 2 on left middle 9 cell square: 2 in R4, R6 → R5C1 2 → R5C4 1.

Scan for 1 on bottom middle 9 cells square: 1 in R9, C4, C5 → R7C6 1.

Scan for 1 on left middle 9 cell square: 1 in R6, C3 → R6C2 1 → R2C1 1.

R1C1 4 as the only digit left in C1 → R1C6 9 → R9C6 2 → R3C6 3 → R3C4 2.

R6C6 4 as the only digit and cell left in C6 → R6C3 8 → R6C9 9 → R4C9 8.

Finishing next stage. No more challenge left.

Results shown.

NYT hard Sudoku 24 Feb 2021: Solution for Beginners Stage 3

R4C3 9 as the only cell for 9 in R4 → R9C4 8 → R9C8 9 → R8C8 8.

Parallel scan for 3 on C4: 3 in R1, R8 → R7C4 3 as the only cell left for 3 in C4.

R6C5 3 as the only cell left for 3 in C5.

R2C5 9 as the only cell left for 9 in C5.

With 4 in top left 9 cell square → R2C2 7 → R2C5 4 → R1C4 7, R7C5 7 → R8C4 4 → R7C3 4 → With 4 in R7C3 → R4C3 6 → R4C2 4 → R1C3 2 → R1C2 6 → R8C3 7 → R8C2 2.

END.

NYT hard Sudoku 24 Feb 2021: Solution for Beginners Stage 4 final

In addition to the four Sudoku techniques explained, the fifth technique of parallel scan has been used in first stage itself.

The hard Sudoku gave away easy single digit candidates at the start but then it raised a block that forced use of possible digit enumeration for a large number of cells.

And breakthrough provided by the single digit lock on 2 in the second stage. Single digit lock identification and use play such an important role so often!

It is a fine hard Sudoku puzzle.

If you are still reading this and not so experienced in solving hard Sudoku puzzles, just leave aside the solution and solve the puzzle yourself.

Suggestion

For full enjoyment, avoid looking into any solution as well as the answer.

The joy of discoveries will then all be yours.


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