MT Calendar Problem 2 - Problem solver solution by Repetition pattern based technique | SureSolv

You are here

For guided learning and practice on Fractions, Surds and Indices follow Comprehensive Guide on Fractions, Surds and Indices with all articles listed

MT Calendar Problem 2 - Problem solver solution by Repetition pattern based technique


Use repetition to discover the key pattern


What will be in the 2012th position if the following sequence continues indefinitely?


Recommended time: 50 secs.

Hint: is in the headline above.

Solution to the MT calendar problem of PROBLEMSOLVING - Discover the key pattern by repeated question, analysis and answer

Writing PROBLEMSOLVING repeatedly and counting the characters to identify the 2012th character is out of question.

It is clear that you have to cut-through the problem using a suitable technique.

The crucial question you ask yourself,

In which situation can I identify a character by its position in the sequence most easily and quickly?

Answer is immediate,

If I start identifying from the first letter of just ONE sequence of PROBLEMSOLVING.

In that case you'll know in a few seconds that B is in 4th position or the character in 10th position is L with total confidence.

From this conclusion you realize that for knowing the character in say, 20th position, you don't have to count the position character by character starting from the very beginning of the repeating sequence,

You would just DROP all complete sequences of PROBLEMSOLVING in 20 characters and start counting and checking in the REMAINING characters left. That would be equivalent to the easiest case of counting and checking in just one number PROBLEMSOLVING, complete or incomplete.

Knowing that you have got the key to the solution, you ask the next crucial question,

How can I get the characters remaining after dropping ALL complete sequences of PROBLEM SOLVING for any given number of characters, say, 2012?

Finally the Repetition pattern based technique is complete with the realization that,

You'll get the remaining characters as the remainder after dividing 2012 by number of characters 14 of the sequence PROBLEMSOLVING.

This essentially is based on the Euclid's division lemma.

Now you have the solution by applying the method.

The solution to the MT Calendar problem of PROBLEMSOLVING

Divide 2012 by 14 to find the remainder to be 10, and 10th character in one number of PROBLEMSOLVING is L.

Answer: The character in 2012th position in the repeated continued sequence of PROBLEMSOLVING is L.

Key concepts and techniques used

By repeated question, analysis and answers you have created and used the Repetition pattern based technique based on Euclid's division lemma, to solve the riddle quickly and systematically without any guesses or random trials.

What you have done is actually Systematic Problem Solving or just Problem Solving in short and with special meaning.

You have done a lot,

You have created a fresh Repetition pattern based technique from scratch simply by repeated asking of most relevant questions, analyzing the problem and finding the answer to the question.

This way of problem solving itself is,

The broad Question, Analysis, Answer technique or QAA technique in short.

Just remember for your continued successful problem solving,

You would be able to solve a problem in an area of knowledge mostly unknown to you if you have access to experts who can provide you with answers to your questions.

This is possible as QAA technique focuses on broad aspects of the problem and not on the details.

More of MT Calendar problems

MT Calendar Problem 2 - Problem solver solution by Repetition pattern based technique

MT Calendar Problem on Ages Solved in Easy Steps 1 - Problem solver solution