## 10 tricky algebra questions for SSC CGL Tier II with answers

It's 10 tricky algebra questions for SSC CGL Tier II to solve in 15 minutes. Take the timed test. Verify from answers. Learn to solve quick from solutions.

To solve such problems quickly, **identification of inherent patterns and use of associated methods are necessary.** These **algebra problem solving techniques** help quick solutions.

For best results **take the timed test first** and then refer to its solution set. Taking the test first, you will be able to **better appreciate** the **pattern based solution methods.**

The **answers and link to the solutions** are at the end.

### 6th set of 10 tricky algebra questions for SSC CGL Tier II - answering time 15 mins

**Q1. **If $\displaystyle\frac{x+y}{z}=2$, then the value of $\displaystyle\frac{y}{y-z}+\displaystyle\frac{x}{x-z}$ is,

- 1
- 2
- 0
- -1

**Q2.** If $3\sqrt{\displaystyle\frac{1-a}{a}}+9=19-3\sqrt{\displaystyle\frac{a}{1-a}}$, the values of $a$ are,

- $\displaystyle\frac{1}{5}$, $\displaystyle\frac{4}{5}$
- $\displaystyle\frac{2}{5}$, $\displaystyle\frac{3}{5}$
- $\displaystyle\frac{1}{10}$, $\displaystyle\frac{9}{10}$
- $\displaystyle\frac{3}{10}$, $\displaystyle\frac{7}{10}$

**Q3. **If $x+y+z=0$, then the value of $\displaystyle\frac{3y^2+x^2+z^2}{2y^2-xz}$ is,

- $2$
- $1$
- $\displaystyle\frac{5}{3}$
- $\displaystyle\frac{3}{2}$

**Q4. **If $3x+4y-2z+9=17$, $7x+2y+11z+8=23$ and $5x+9y+6z-4=18$ then the value of $x+y+z-34$ is,

- $-28$
- $-31$
- $-14$
- $-45$

**Q5. **If $x$, $y$, and $z$ are three factors of $a^3-7a-6$, then the value of $x+y+z$ is,

- 3a
- a
- 3
- 6

**Q6.** If $3x+5y+7z=49$ and $9x+8y+21z=126$, then what is the value of $y$?

- 3
- 5
- 2
- 4

** Q7.** $x$, $y$ and $z$ are real numbers. If $x^3+y^3+z^3=13$, $x+y+z=1$ and $xyz=1$, then the value of $xy+yz+zx$ is,

- $1$
- $-1$
- $3$
- $-3$

** Q8.** Three numbers are in arithmetic progression. The sum of the numbers is 30 and the product is 910. The greatest of the three numbers is,

- 17
- 10
- 13
- 15

**Q9.** The value of $x$ which satisfies the equation, $\displaystyle\frac{x+a^2+2c^2}{b+c}+\displaystyle\frac{x+b^2+2a^2}{c+a}+\displaystyle\frac{x+c^2+2b^2}{a+b}=0$ is,

- $a^2+b^2+c^2$
- $a^2+2b^2+c^2$
- $-(a^2+b^2+2c^2)$
- $-(a^2+b^2+c^2)$

** Q10.** If $ax+by+cz=20$, $a^2+b^2+c^2=16$ and $x^2+y^2+z^2=25$, then the value of $\displaystyle\frac{a+b+c}{x+y+z}$ is,

- $\displaystyle\frac{4}{5}$
- $\displaystyle\frac{3}{5}$
- $\displaystyle\frac{5}{4}$
- $\displaystyle\frac{5}{3}$

To know how to solve the problems quickly in a few steps, refer to the solutions,

**SSC CGL Tier II Solution set 17, Algebra 6.**

### 6th set of 10 tricky algebra questions for SSC CGL Tier II

**Problem 1.** **Answer:** Option b: 2.

**Problem 2.** **Answer:** Option c : $\displaystyle\frac{1}{10}$, $\displaystyle\frac{9}{10}$.

**Problem 3.** **Answer:** Option a: $2$.

**Problem 4.** **Answer:** Option b: $-31$.

**Problem 5.** **Answer:** Option a: 3a.

**Problem 6.** **Answer:** Option a : 3.

**Problem 7.** **Answer:** Option d: $-3$.

**Problem 8.** **Answer:** Option c: 13.

**Problem 9.** **Answer:** Option d: $-(a^2+b^2+c^2)$.

**Problem 10.** **Answer:** Option a: $\displaystyle\frac{4}{5}$.

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