SSC CGL Tier II level Question Set 3, Algebra 3

Submitted by Atanu Chaudhuri on Sun, 23/10/2016 - 13:09

3rd SSC CGL Tier II level Question Set, 3rd on Algebra

SSC CGL Tier 2 question set 3 algebra3

This is the 3rd question set of 10 practice problem exercise for SSC CGL Tier II exam and also the 3rd on topic Algebra.

For maximum gains, the test should be taken first, that is obvious. But more importantly, to absorb the concepts, techniques and deductive reasoning elaborated through the solutions, one must solve many problems in a systematic manner using this conceptual analytical approach.

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3rd question set - 10 problems for SSC CGL exam: 3rd on topic Algebra - answering time 12 mins

Q1. If $4y-3x=13$ and $xy=14$, then $64y^3-27x^3$ is,

8479
8400
8740
8749

Q2. If $x=(0.09)^2$, $y=\displaystyle\frac{1}{(0.09)^2}$ and $z=(1- 0.09)^2 - 1$, then which of the following relations is true?,

$y \lt x$ and $x=z$
$y \lt z \lt x$
$z \lt x \lt y$
$x \lt y$ and $x=z$

Q3. Minimum value of $x^4 +\displaystyle\frac{1}{x^4+1} - 3$ is,

$0$
$-1$
$-2$
$-3$

Q4. If $\displaystyle\frac{p}{3}=\frac{q}{2}$ then the value of $\displaystyle\frac{2p+3q}{3p-2q}$ is,

$1$
$\displaystyle\frac{12}{5}$
$\displaystyle\frac{5}{12}$
$\displaystyle\frac{12}{7}$

Q5. If $(a-4)^2 + (b-9)^2+(c-3)^2=0$, then the value of $\sqrt{a+b+c}$ is,

$\pm{4}$
$4$
$-4$
$\pm{2}$

Q6. If $\displaystyle\frac{1}{x+y}=\displaystyle\frac{1}x+\displaystyle\frac{1}{y}$, where, $x \neq 0$, $y \neq 0$ and $x \neq y$, the value of $x^3-y^3$ is,

$0$
$2$
$1$
$-1$

Q7. If $a^x=(x+y+z)^y$, $a^y=(x+y+z)^z$ and $a^z=(x+y+z)^x$ find the value of $a+b+c$ where $a \neq 0$.

$0$
$1$
$a^3$
$a$

Q8. If $\displaystyle\frac{x-a^2}{b^2+c^2} + \displaystyle\frac{x-b^2}{c^2+a^2} +\displaystyle\frac{x-c^2}{a^2+b^2} =3$ then the value of $x$ is,

$a^2+b^2$
$a^2+b^2+c^2$
$a^2+b^2-c^2$
$a^2-b^2-c^2$

Q9. If $ax^2+bx+c=a(x-p)^2$, then the correct relation between $a$, $b$ and $c$ would be,

$2b=a+c$
$b^2=4ac$
$b^2=ac$
$abc=1$

Q10. If $\displaystyle\frac{y}{x} - \displaystyle\frac{x}{y}=3$, then find the value of $\displaystyle\frac{x^3}{y^3} + \displaystyle\frac{y^3}{x^3}$.

$10\sqrt{3}$
$10\sqrt{13}$
$13\sqrt{3}$
$13\sqrt{10}$

For detailed conceptual solution to the questions, refer to SSC CGL Tier II level Solution set 3 Algebra 3.

Answers to the questions

Problem 1: Answer: Option d: 8749.

Problem 2: Answer: Option c : $z \lt x \lt y$.

Problem 3: Answer: Option c: $-2$.

Problem 4: Answer: Option b: $\displaystyle\frac{12}{5}$.

Problem 5: Answer: Option b: 4.

Problem 6: Answer: Option a : 0.

Problem 7: Answer: Option d: $a$.

Problem 8: Answer: Option b: $a^2+b^2+c^2$.

Problem 9: Answer: Option b: $b^2=4ac$.

Problem 10: Answer: Option b: $10\sqrt{13}$.

Additional help on SSC CGL Algebra

Apart from a large number of question and solution sets and a valuable article on "7 Steps for sure success on Tier 1 and Tier 2 of SSC CGL" rich with concepts and links, you may refer to our other articles specifically on Algebra listed on latest shown first basis,