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SSC CGL Tier II

Highlights

Guidelines, Question sets and Solution sets specially tailored for SSC CGL Tier II test. Students should refer to tutorials for the required base concepts and then only take the tests. The solution sets provide conceptual analytical efficient solutions. After taking a question set, Student need to go through the corresponding solution set with focused attention for effective and assured problem solving skill improvement.

SSC CGL Tier II level Solution Set 26, Time and work problems 2

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This is the 26th solution set of 10 practice problem exercise for SSC CGL Tier II exam and the 2nd on Time and work problems. For maximum gains, the test should be taken first, that is obvious. But more importantly, to absorb the concepts, techniques and deductive reasoning elaborated through these solutions, one must solve many problems in a systematic manner using this conceptual analytical approach. One can learn well only by practicing learning by doing...

SSC CGL Tier II level Question Set 26, Time and work problems 2

thumb_ssc-cgl-tier2-question-set-26-time-work-work-wages-2

This is the 26th question set of 10 practice problem exercise for SSC CGL Tier II exam and the 2nd on Time and work problems. For maximum gains, the test should be taken first, that is obvious. But more importantly, to absorb the concepts, techniques and deductive reasoning elaborated through the solutions in the corresponding solution set, one must solve many problems in a systematic manner using conceptual analytical approach. One can learn well only by practicing learning by doing...

SSC CGL Tier II level Solved Question Set 25 on mixture or alligation 2

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This is the 25th set of solved questions of 10 practice problem exercise for SSC CGL Tier II exams and 2nd on purely mixture or alligation problems. The questions are followed by answers and then the detailed conceptual solution with explanation. The solutions should be referred to only after attempting the questions...

Algebraic proof of Least value of sum of reciprocals for any number of positive variables

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The result of the least value of sum of reciprocals, used in Algebra represents an important principle of value sharing.

For two positive real variables $a$ and $b$ for example, if $a+b=1$, the least value of sum of reciprocals of $a$ and $b$ will occur when the value of the sum 1 is shared equally between the two variables. This remarkable equal value sharing principle hold true for any number of variables as well as for any positive sum of the variables...

SSC CGL Tier II level Solved Question Set 24 on mixture or alligation 1

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This is the 24th set of solved questions of 10 practice problem exercise for SSC CGL Tier II exams and 1st on purely mixture or alligation problems. The questions are followed by answers and then the detailed conceptual solution with explanation. The solutions should be referred to only after attempting the questions...

SSC CGL Tier II level Solution Set 22, Ratio proportion 1

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This is the 22nd solution set of 10 practice problem exercise for SSC CGL Tier II exam and 1st on topic Ratio and Proportion. Students should complete the corresponding question set in prescribed time first and then only refer to this solution set for extracting maximum benefits from this resource. The set of 10 problems being a bit more difficult than usual, 15 minutes answering time was given...

SSC CGL Tier II level Question Set 22, Ratio proportion 1

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This is the 22nd question set of 10 practice problem exercise for SSC CGL Tier II exam and 1st on topic Ratio and Proportion. Students should complete this question set in prescribed time first and then only refer to the corresponding solution set for extracting maximum benefits from this resource. This set of 10 problems being a bit more difficult than usual, 15 minutes answering time was given...

How to solve a SSC CGL level tricky age ratio problem lightning fast

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Use of the rich ratio technique of multiple of ratio value helps to solve a broad spectrum of ratio problems and specifically many standard number or age ratio problems elegantly in a few steps much faster than conventional procedural methods. The chosen problem here is a tricky one and we will solve it using multiple of ratio value technique as well as conventionally to highlight the power of the rich ratio technique...

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