Third SSC CGL level Question Set, topic Arithmetic Number system
This is the third question set of 10 practice problem exercise for SSC CGL exam on topic Arithmetic Number System. Students must complete this question set in prescribed time first and then only refer to the corresponding solution set.
It is emphasized here that answering in MCQ test is not at all the same as answering in a school test where you need to derive the solution in perfectly elaborated steps.
In MCQ test instead, you need basically to deduce the answer in shortest possible time and select the right choice. None will ask you about what steps you followed.
Based on our analysis and experience we have seen that, for accurate and quick answering, the student
- must have complete understanding of the basic concepts of the topics
- is adequately fast in mental math calculation
- should try to solve each problem using the most basic concepts in the specific topic area and
- does most of the deductive reasoning and calculation in his head rather than on paper.
Actual problem solving happens in items 3 and 4 above. But how to do that?
You need to use your problem solving abilities only. There is no other recourse.
Third question set- 10 problems for SSC CGL exam: topic Arithmetic Number System - time 20 mins
Q1. If $3^{4x}\times{9^{6x}} = 81^8$, $x=?$,
- 2
- 3
- 4
- 8
Q2. Which one of the following is a perfect square as well as a cube?
- 81
- 125
- 343
- 64
Q3. If the digits of a two digit number are interchanged in position, the absolute value of the difference of the two numbers would be always divisible by,
- 5
- 7
- 9
- 11
Q4. If two bells chime at intervals of 4 mins and 15 mins, after how long would they chime together first if they had chimed together in the beginning?
- 26 mins
- 52 mins
- 1 hour 18 minutes
- 1 hour
Q5. How many numbers from 20 to 50 have no number from 2 to 10 as factors?
- 0
- 14
- 7
- 4
Q6. $\displaystyle\frac{256\times{256} - 144\times{144}}{112}$ is,
- 420
- 400
- 360
- 380
Q7. If the digits in the unit's and ten's places of a three digit number are interchanged, the new number formed is found to be larger than the original by 63. All possible values that the unit's digit of the original number can take are,
- 7, 8, 9
- 2, 7, 9
- 0, 1, 2
- 1, 2, 8
Q8. The sum of all the three digit numbers, each of which on division by 5 leaves a remainder 3 is,
- 180
- 1550
- 6995
- 99090
Q9. Unit's digit in $264^{102} + 264^{103}$ is,
- 0
- 4
- 6
- 8
Q10. Unit's digit of $2137^{754}$ is,
- 1
- 3
- 7
- 9
For detailed conceptual solutions read the article,
SSC CGL level Solution Set 3 on Arithmetic Number system, and
For detailed video solutions of these 10 questions watch,
Guided help on Number system, HCF LCM in Suresolv
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