Questions on Algebra for SSC CGL Set 81 with answers
Solve 10 Questions on Algebra for SSC CGL Set 81 in 12 minutes. Verify solutions from answers. Learn to solve quickly the right way from paired solutions.
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10 Questions on Algebra for SSC CGL Set 81 - answering time 12 mins
Q1. If $x+\displaystyle\frac{1}{x}=3$, then value of $x^8+\displaystyle\frac{1}{x^8}$ is,
- 2213
- 2207
- 2201
- 2203
Q2. If $(x-4)(x^2+4x+16)=x^3-p$, then value of $p$ is,
- 27
- 0
- 8
- 64
Q3. If $a+b+c=15$ and $\displaystyle\frac{1}{a}+\displaystyle\frac{1}{b}+\displaystyle\frac{1}{c}=\displaystyle\frac{71}{abc}$, then the value of $a^3+b^3+c^3-3abc$ is,
- 180
- 160
- 220
- 200
Q4. If $x=12$, and $y=4$, then the value of $(x+y)^{\displaystyle\frac{x}{y}}$ is,
- 570
- 48
- 1792
- 4096
Q5. If $xy+yz+zx=1$, then the value of $\displaystyle\frac{1+y^2}{(x+y)(y+z)}$ is,
- 1
- 4
- 2
- 3
Q6. If $x+y+z=0$, then the value of $\displaystyle\frac{x^2}{3z}+\displaystyle\frac{y^3}{3xz}+\displaystyle\frac{z^2}{3x}$ is,
- $0$
- $3y$
- $y$
- $xz$
Q7. If the expression $(px^3-2x^2-qx+18)$ is completely divisible by $(x^2-9)$, then the ratio of $p$ to $q$ is,
- 9 : 1
- 1 : 9
- 3 : 1
- 1 : 3
Q8. If $\displaystyle\frac{x}{3}+\displaystyle\frac{3}{x}=1$, then the value of $x^3$ is,
- $0$
- $27$
- $-27$
- $1$
Q9. If $\displaystyle\frac{1}{x}+\displaystyle\frac{1}{y}+\displaystyle\frac{1}{z}=0$ and $x+y+z=9$, then the value of $x^3+y^3+z^3-3xyz$ is,
- 81
- 6561
- 729
- 361
Q10. If $a(a+b+c)=45$, $b(a+b+c)=75$ and $c(a+b+c)=105$, then the value of $a^2+b^2+c^2$ is,
- 75
- 83
- 225
- 217
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SSC CGL Level Solution set 81 Algebra 17.
Answers to the questions on algebra for SSC CGL Set 81
Problem 1. Answer: Option b: 2207.
Problem 2. Answer: Option d : 64.
Problem 3. Answer: Option a: 180.
Problem 4. Answer: Option d: 4096.
Problem 5. Answer: Option a: 1.
Problem 6. Answer: Option c : $y$.
Problem 7. Answer: Option b: 1 : 9.
Problem 8. Answer: Option c: $-27$.
Problem 9. Answer: Option c: 729.
Problem 10. Answer: Option b: 83.
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