## 2nd Set of 10 Solved SSC CHSL time and work questions

Practice on 10 SSC CHSL time and work test questions in set 2.

Questions are solved by time and work techniques: working together, man hour, work rate, work wage.

The second set of solved time and work questions contains,

**10 carefully selected questions on Time and work for SSC CHSL**to be answered in 15 minutes.**Answers**to the questions, and**Quick solutions**to the questions.

For best results,

**Take the test first**with timer on.**Stop at**15 minutes.**Verify**how far your answers are correct from the answers.**Clear your doubts**and**learn**how to solve the questions quick and easy from the detailed solution set.

For quick solution of the questions, *time and work concepts* along with concepts on ratio and proportion, product of ratios, unitary method are used.

### SSC CHSL time and work questions, Practice Set 2: Answering time 15 mins

**Q1. **If the work done by $(x-1)$ men in $(x+1)$ days is to the work done by $(x+2)$ men in $(x-1)$ days are in the ratio $9:10$, then the value of $x$ is,

- 8
- 7
- 6
- 5

**Q2.** 3 men and 7 women can do a job in 5 days, while 4 men and 6 women do it in 4 days. The number of days required for a group of 10 women working together at the same rate as before to finish the job is,

- 30 days
- 40 days
- 36 days
- 20 days

**Q3. **If there is a reduction in the number of workers in a factory in the ratio of $15:11$ and an increment of wages in the ratio of $22:25$, the ratio by which the total wages of the workers would be decreased is,

- $3:7$
- $5:6$
- $6:5$
- $3:5$

**Q4. **Debu and Monu take a piece of work for Rs.28,800. One alone could do it in 36 days and the other in 48 days. With the assistance of an expert they finish it in 12 days. How much remuneration the expert should get?

- Rs.10,000
- Rs.12,000
- Rs.18,000
- Rs.16,000

**Q5. **It was planned to construct a road 5 km long in 100 days and 280 workers were employed for the job. But after 80 days it was found that only $3\displaystyle\frac{1}{2}$ Km of the road was completed. How many more men need to be employed now to complete the work in planned time?

- 200
- 80
- 100
- 480

**Q6.** P can complete $\displaystyle\frac{1}{4}$th of a work in 10 days. Q can complete 40% of the same work in 15 days. R completes $\displaystyle\frac{1}{3}$rd of the work in 13 days and S completes $\displaystyle\frac{1}{6}$th of the work in 7 days. Who will be able to complete the work earliest?

- S
- P
- Q
- R

**Q7.** A and B can do a piece of work in 72 days, B and C can do it in 120 days and A and C can do it in 90 days.. When A, B and C work together, how much work will be finished by them in 3 days?

- $\displaystyle\frac{1}{40}$
- $\displaystyle\frac{1}{10}$
- $\displaystyle\frac{1}{20}$
- $\displaystyle\frac{1}{30}$

**Q8.** 40 men can complete a work in 18 days. Eight days after they started working together, 10 more men joined them. How many days will they now take to complete the remaining work?

- 12 days
- 8 days
- 10 days
- 6 days

**Q9.** A can do as much work as B and C together can do. A and B can do a piece of work in 9 hours 36 mins and C can do it in 48 hours. The time that B will take to complete the work alone is,

- 18 hours
- 12 hours
- 30 hours
- 24 hours

**Q10.** A and B can do a work in 18 and 24 days respectively. They worked together for 8 days and then A left. The remaining work was finished by B in,

- $8$ days
- $5\displaystyle\frac{1}{3}$ days
- $10$ days
- $5$ days

### Answers to the SSC CHSL Time and Work Questions Practice Set 2

**Q1. Answer:** Option a: 8.

**Q2. Answer:** Option d : 20 days.

**Q3. Answer:** Option c: $6:5$.

**Q4. Answer:** Option b: Rs.12,000.

**Q5. Answer:** Option a: 200.

**Q6. Answer:** Option c : Q.

**Q7. Answer:** Option c: $\displaystyle\frac{1}{20}$.

**Q8. Answer:** Option b: 8 days.

**Q9. Answer:** Option d: 24 hours.

**Q10. Answer:** Option b: $5\displaystyle\frac{1}{3}$ days.

### Solutions to the SSC CHSL Time and Work Questions Practice Set 2: Answering time was 15 mins

**Q1. **If the work done by $(x-1)$ men in $(x+1)$ days is to the work done by $(x+2)$ men in $(x-1)$ days are in the ratio $9:10$, then the value of $x$ is,

- 8
- 7
- 6
- 5

** Solution 1: Problem analysis and solution by using man days as measure of work amount**

By the first condition, work done by $(x-1)$ men in $(x+1)$ days is,

$W_1=(x-1)(x+1)$ man days.

We have expressed the work amount in terms of man days.

Similarly in the second case, the work done,

$W_2=(x+2)(x-1)$ man days.

By the third condition,

The two amounts of work done are in the ratio $9:10$. So,

$\displaystyle\frac{W_1}{W_2}=\frac{(x-1)(x+1)}{(x+2)(x-1)}=\frac{9}{10}$,

Or, $\displaystyle\frac{x+1}{x+2}=\frac{9}{10}$.

Cross-multiplying and simplifying,

$x=8$.

**Answer:** Option a: 8.

**Key concepts used:** * Work time concept* --

*--*

**Man days concept***.*

**Ratio and proportion****Q2.** 3 men and 7 women can do a job in 5 days, while 4 men and 6 women do it in 4 days. The number of days required for a group of 10 women working together at the same rate as before to finish the job is,

- 30 days
- 40 days
- 36 days
- 20 days

**Solution 2: Problem solving by Work rate technique**

Here two cases of work completion with two different combinations of workers are given.

Assume **work portion done by a man and a woman in a day** as, $M$ and $W$ respectively. These are the corresponding work rates. This is **Work rate technique.**

In this technique, work variables are expressed as work rates and the fraction arithmetic is transferred to the RHS on total work amount making it much simpler.

Assume work amount as $W_A$.

By the first two conditions then,

$5(3M+7W)=W_A$,

Or, $15M+35W=W_A$, and,

$4(4M+6W)=W_A$,

Or, $16M+24W=W_A$.

$M$ to be eliminated to get the value of work rate of a woman in terms of work portion done in a day.

Multiply the first equation by 16, the second by 15 and subtract the second result from the first,

$W_A=W(16\times{35}-15\times{24})$

$=20W(28-18)$

$=200W$.

As 10 women work in the third case,

$W_A=20(10W)$.

10 women working together will take 20 days to complete the work.

**Answer:** Option d: 20 days.

**Key concepts used:** **Work rate technique -- Work time concept -- Solution to a pair of linear algebraic equation****.**

After writing first two equations, rest of the calculations could be carried out in mind.

**Q3. **If there is a reduction in the number of workers in a factory in the ratio of $15:11$ and an increment of wages in the ratio of $22:25$, the ratio by which the total wages of the workers would be decreased is,

- $3:7$
- $5:6$
- $6:5$
- $3:5$

**Solution 3: Problem analysis and solution by Ratio and proportion and Product of ratios concepts**

$\text{Total wage }=\text{Number of workers}\times{\text{Wage per worker}}$.

So multiplying the two given ratios we will get the ratio of total wages before and after,

$\text{Ratio of total wage of workers}=\displaystyle\frac{15}{11}\times{\displaystyle\frac{22}{25}}$

$=\displaystyle\frac{6}{5}$.

**Answer:** Option c: $6:5$.

**Key concepts used: Work wage concept -- Ratio proportion concept -- Product of ratios -- HCF reintroduction technique**

**.**

#### Mathematical explanation of multiplication of two ratios - what it means

Let total wages in the before and after situations be $TW_1$ and $TW_2$.

In the first case, the before and after ratio of number of workers is,

$\displaystyle\frac{15}{11}=\frac{15x}{11x}$, where $15x$ and $11x$ are the actual number of workers and $x$ is the canceled out HCF reintroduced.

Similarly in the second case, the before and after ratio of wage per worker is,

$\displaystyle\frac{22}{25}=\frac{22y}{25y}$, where $22y$ and $25y$ are the actual wage per worker and $y$ is the canceled out HCF reintroduced.

As total wage is the product of number of workers and wage per worker,

$TW_1=xy(15\times{22})$, and

$TW_2=xy(11\times{25})$.

Taking ratio of the two total wages we get,

$\displaystyle\frac{TW_1}{TW_2}=\frac{15}{11}\times{\frac{22}{25}}$

$=\displaystyle\frac{6}{5}$.

You don't have to deduce the answer this way. This explanation shows how a product of two ratios can result in a third ratio. In fact, with clear concepts, the problem can easily be solved in mind.

**Q4. **Debu and Monu take a piece of work for Rs.28,800. One alone could do it in 36 days and the other in 48 days. With the assistance of an expert they finish it in 12 days. How much remuneration the expert should get?

- Rs.10,000
- Rs.12,000
- Rs.18,000
- Rs.16,000

**Solution 4: Problem solving by earning to work portion done proportionality**

By earning to work portion done proportionality concept,

Total earning of a worker is directly proportional to the portion of work done by the worker.

The portion of work completed by Debu and Monu in 12 days of working together is,

$\displaystyle\frac{12}{36}+\displaystyle\frac{12}{48}=\displaystyle\frac{1}{3}+\displaystyle\frac{1}{4}=\displaystyle\frac{7}{12}$ portion of the work.

As total earning is directly proportional to the portion of total work done which is worth a total earning of Rs.28,800, in 12 days of working together Debu and Monu will earn,

$\displaystyle\frac{7}{12}$th of the total earning, and the expert will earn the rest as,

$\displaystyle\frac{5}{12}$th of total earning

$=\displaystyle\frac{5}{12}\times{\text{Rs.28,800}}$

$=\text{Rs.12,000}$.

**Answer:** Option b: Rs.12,000.

**Key concepts used: Work wage concept -- Work rate concept -- Earning proportional to work portion done concept -- Working together concept****.**

**Q5. **It was planned to construct a road 5 km long in 100 days and 280 workers were employed for the job. But after 80 days it was found that only $3\displaystyle\frac{1}{2}$ km of the road was completed. How many more men need to be employed now to complete the work in planned time?

- 200
- 80
- 100
- 480

**Solution 5: Problem analysis and solution by man days concept**

We will use man days as work measure.

280 workers working for 80 days results in,

$280\times{80}\text{ man days}=3\displaystyle\frac{1}{2}=\displaystyle\frac{7}{2}$ km of road work

Simplifying we get the work equivalence of,

$80\times{80}\text{ man days}=1$ km of road work.

Leftover work is, $5-3\displaystyle\frac{1}{2}=\displaystyle\frac{3}{2}$ km of road work

If $x$ be the number of workers completing this leftover work in 20 days we have the man days equivalence as,

$20x\text{ man days}=\displaystyle\frac{3}{2}$km of road work,

$=\displaystyle\frac{3\times{80}\times{80}}{2}$ man days of work, substituting man days equivalent to 1 km of road work,

Or, $x=480$ men

Extra number of worker required would then be,

$480-280=200$.

**Answer:** Option a: 200.

*Key concepts used:* **Man days as work measure concept****.**

**Q6.** P can complete $\displaystyle\frac{1}{4}$th of a work in 10 days. Q can complete 40% of the same work in 15 days. R completes $\displaystyle\frac{1}{3}$rd of the work in 13 days and S completes $\displaystyle\frac{1}{6}$th of the work in 7 days. Who will be able to complete the work earliest?

- S
- P
- Q
- R

**Solution 6 - Problem analysis and solution by comparing number of days required to complete the work**

P can complete $\displaystyle\frac{1}{4}$th of a work in 10 days,

So, P completes the whole work in 40 days.

Q can complete 40% or $\displaystyle\frac{2}{5}$th of the same work in 15 days,

So, Q completes the whole work in $\displaystyle\frac{75}{2}=37.5$ days.

R completes $\displaystyle\frac{1}{3}$rd of the work in 13 days,

So, R completes the whole work in 39 days.

S completes $\displaystyle\frac{1}{6}$th of the work in 7 days,

So, S completes the whole work in 42 days.

Out of the four then Q takes minimum time of 37.5 days to complete work.

**Answer:** Option c : Q.

**Key concepts used:** ** Working time concept -- Work completion time as product of inverse of work portion and time to do the portion -- unitary method**.

**Q7.** A and B can do a piece of work in 72 days, B and C can do it in 120 days and A and C can do it in 90 days. When A, B and C work together, how much work will be finished by them in 3 days?

- $\displaystyle\frac{1}{40}$
- $\displaystyle\frac{1}{10}$
- $\displaystyle\frac{1}{20}$
- $\displaystyle\frac{1}{30}$

**Solution 7 - Problem analysis and excution by Work rate technique and working together concepts**

Assuming $A_w$, $B_w$ and $C_w$ as the work rate or work portion done in a day by A, B and C respectively, by the three given conditions,

$A_w+B_w=\displaystyle\frac{1}{72}W$, assuming total work as $W$,

$B_w+C_w=\displaystyle\frac{1}{120}W$, and

$C_w+A_w=\displaystyle\frac{1}{90}W$.

Adding the three we get work portion done in a day when A, B and C work together as,

$A_w+B_w+C_w=\displaystyle\frac{1}{2}\left(\displaystyle\frac{1}{72}+ \displaystyle\frac{1}{120}+\displaystyle\frac{1}{90}\right)W$

$=\displaystyle\frac{1}{60}W$.

So A, B, and C working together, will complete $\displaystyle\frac{1}{60}$th of the work in 1 day and $\displaystyle\frac{1}{20}$ th of the work in 3 days.

**Answer:** Option c: $\displaystyle\frac{1}{20}$.

** Key concepts used:** ** Work rate of each worker in terms of work portion done in a day **--

*--*

**Work rate technique**

**Working together concept, work portion done by workers working together is sum of their work rates -- Summing up three equations gives us the work portion done by all three together in a day.****Q8.** 40 men can complete a work in 18 days. Eight days after they started working together, 10 more men joined them. How many days will they now take to complete the remaining work?

- 12 days
- 8 days
- 10 days
- 6 days

** Solution 8 - Problem analysis and execution by man days concept**

40 men complete a work in 18 days, and so the work amount is,

$40\times{18}=720$ man days.

In first 8 days 40 men complete, 320 mandays of work leaving 400 mandays work yet to be done.

On 9th day 10 more men joining, the team strength becomes 50 men.

To complete the left-out work of 400 mandays, this team of 50 men will require then,

$\displaystyle\frac{400}{50}=8$ days.

**Answer:** Option b: 8 days.

**Key concepts used:** **Man days as work measure concept -- left-out work concept.**

**Q9.** A can do as much work as B and C together can do. A and B can do a piece of work in 9 hours 36 mins and C can do it in 48 hours. The time that B will take to complete the work alone is,

- 18 hours
- 12 hours
- 30 hours
- 24 hours

**Solution 9 - Problem analysis and execution by Work rate as work portion done in a day and Working together concept by adding work rates**

A and B working together can complete the work in 9 hours 36 minutes or $9\displaystyle\frac{3}{5}=\frac{48}{5}$ hours.

Adopting **Work rate technique**, we assume work rates $a$, $b$ and $c$ as portion of work done in a day by A, B and C respectively, and $W$ as the whole work amount.

So by the second condition of A and B together doing the whole work in $\displaystyle\frac{48}{5}$ hours, we get **one day work equivalence** as,

$a+b=W\div{\displaystyle\frac{48}{5}}=\displaystyle\frac{5W}{48}$, Assuming $W$ as the whole work amount.

C does the work in 48 hours. So,

$c=\displaystyle\frac{W}{48}$

Also given, $a=b+c$. Substituting in the first equation,

$a+b=2b+c=\displaystyle\frac{5W}{48}$,

Or, $2b+\displaystyle\frac{W}{48}=\displaystyle\frac{5W}{48}$,

Or, $2b=\displaystyle\frac{W}{12}$,

Or, $b=\displaystyle\frac{W}{24}$.

It means B will complete the work in 24 hours.

**Answer:** Option d: 24 hours.

**Key concepts used:** * Work rate technique -- Working together concept* --

**Efficient simplification.****Q10.** A and B can do a work in 18 and 24 days respectively. They worked together for 8 days and then A left. The remaining work was finished by B in,

- $8$ days
- $5\displaystyle\frac{1}{3}$ days
- $10$ days
- $5$ days

**Solution 10 - Problem analysis and solution by work rate and working together concepts**

In 8 days, A and B working together complete portion of total work,

$8\left(\displaystyle\frac{1}{18}+\displaystyle\frac{1}{24}\right)=\displaystyle\frac{7}{9}$

So the leftout work is $\displaystyle\frac{2}{9}$th of the whole wotk.

B does the whole work in 24 days, so he will do $\displaystyle\frac{2}{9}$th of the whole work in,

$24\times{\displaystyle\frac{2}{9}}=\displaystyle\frac{16}{3}=5\displaystyle\frac{1}{3}$ days.

**Answer: **Option b: $5\displaystyle\frac{1}{3}$ days.

**Key concepts used:** **Work rate concept -- Working together concept.**

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