Tutorials | SureSolv

Tutorials

In work life and personal life often we need to learn the basics on a subject quickly. Usually it is not easy to acquire the basic concepts on any subject reliably in a short time from a concise material.

Basic concepts on any subject form the foundation, but generally we have found it is not easy to build it in a short time. Our focus here is on base concepts in a concise form that can be learned quickly and be used as a launch pad for further learning and subject specific problem solving.

Often we added a rich concept layer derived from the base concepts that helps to solve more complex problems with great ease. For us, it is a two layer concept model: Base concepts and Rich concepts derived from base concepts. Objective is efficient problem solving.

Subcategories

Basic maths: Basic concepts on maths. The content is primarily targeted for competitive test requirements.

Reasoning and logic analysis: Tutorials, problems and puzzles on competitive test reasoning and logic analysis.

How to find perfect and approximate square root of integers or decimals

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For most needs of finding square root, if we remember by heart squares and cubes of a few common integers, using quick factorization we can figure out the square roots or cube roots of numbers be it integer or decimal. But occasionally, in a few specific types of arithmetic problems, there is no other option than to actually evaluate the square root of a number following a method specifically tailored for the purpose...

Partially hidden Componendo dividendo revealed to solve a not so difficult Algebra problem in minimum time 7

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In a problem in which Componendo dividendo is partially hidden, expression with distinctive pattern exists, but its inseparable pair, the fraction of two variables involved in the distinctive expression is not visible. Uncovering and using Componendo dividendo in such a problem invariably gives you the solution faster than any other method. But revealing even partially hidden pattern is possible only when you look for it...

Hidden Componendo dividendo uncovered to solve difficult Algebra problems quickly 6

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Occasionally the distinctive expression and its inseparable companion fraction of two componendo dividendo variables, both exist in given and target expressions, but in hidden form. With a closer look and component expression substitution, once possibility of using componendo dividendo is revealed, the problem can be solved in mind quickly, faster than any other method. These form another important class of hidden componendo dividendo problems that need uncovering...

Componendo dividendo uncovered to solve difficult Algebra problems quickly 5

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Occasionally the distinctive expression appears in one of the expressions, but its inseparable pair, the fraction of the two variables, is not readily available in the problem statement. We say in these cases that componendo dividendo appears in partial form, and the problem is of hidden componendo dividendo type. We need to change the given expression to match the target expression in such cases...

Componendo dividendo adapted to solve difficult Algebra problems quickly 4

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When the problem appears in a form exactly suitable for applying the method, problem solving is trivial and very easy. The real challenge lies in problems where, there is some pattern similar to Componendo dividendo in the problem, but only partially, so at first glance we don't consider Componendo dividendo as the suitable approach...

How to solve Surds part 3, Surd expression comparison and ranking

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In this third tutorial on how to solve surd problems, we will take up explaining two related problem classes, namely, two-term surd expression comparison and ranking. First we will state and explain two important rich concepts used for quick solution and then apply the rich concepts in solving chosen SSC CGL level problems...

How to solve Surds part 2, double square root surds and surd term factoring

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In this second tutorial we will explain how a surd expression under a second square root is dealt with as well as explain two other typical surd problem solving techniques, namely, surd term factoring and coefficient equalization of surd and non-surd terms in a surd equation. We will explain through the process of solving chosen SSC CGL level problems...

How to solve high level box positioning reasoning puzzle for SBI PO quickly 9

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In this ninth tutorial session, while solving a high level hard box positioning reasoning puzzle, detailed logic analysis on placement of temporary bonded member structures onto the main logic table provided the breakthroughs...

Componendo dividendo applied on number system and ratio proportion problems

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Because of the easy systematic steps most likely we would be able to solve a problem quickly and wholly in mind by Componendo dividendo. In this session we have shown how problems not directly conforming to the Componendo dividendo can still be solved quickly using the concepts of Componendo dividendo...

How to solve high level nine position circular seating reasoning puzzles for SBI PO quickly 8

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In this eighth tutorial session, while solving a high level nine person circular seating reasoning puzzle, we will give more time to analysis of all the logic conditions together. With a feel of the nature of the problem then, we will identify the main barrier to the problem, select the most promising logic conditions to process first, and take the next steps to remove the main barrier...

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